2x+(16/x^2)=0

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Solution for 2x+(16/x^2)=0 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+16/(x^2) = 0

2*x^1+16*x^-2 = 0

(2*x^3+16*x^0)/(x^2) = 0 // * x^4

x^2*(2*x^3+16*x^0) = 0

x^2

2*x^3+16 = 0

{ 1, -1, 2, -2, 4, -4, 8, -8, 16, -16 }

1

x = 1

2*x^3+16 = 18

1

-1

x = -1

2*x^3+16 = 14

-1

2

x = 2

2*x^3+16 = 32

2

-2

x = -2

2*x^3+16 = 0

-2

x+2

2*x^2-4*x+8

2*x^3+16

x+2

-2*x^3-4*x^2

16-4*x^2

4*x^2+8*x

8*x+16

-8*x-16

0

2*x^2-4*x+8 = 0

DELTA = (-4)^2-(2*4*8)

DELTA = -48

DELTA < 0

x in { -2}

x = -2

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